Base | Representation |
---|---|
bin | 110100110110100100… |
… | …0101110110111000011 |
3 | 101211222000120021211201 |
4 | 1221231020232313003 |
5 | 3324422014432311 |
6 | 124050302122031 |
7 | 11125432254643 |
oct | 1515510566703 |
9 | 354860507751 |
10 | 113500155331 |
11 | 44153973672 |
12 | 19bb6b80317 |
13 | a91a6bc134 |
14 | 56c9dc2523 |
15 | 2e445359c1 |
hex | 1a6d22edc3 |
113500155331 has 2 divisors, whose sum is σ = 113500155332. Its totient is φ = 113500155330.
The previous prime is 113500155271. The next prime is 113500155343. The reversal of 113500155331 is 133551005311.
It is a strong prime.
It is an emirp because it is prime and its reverse (133551005311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113500155331 - 27 = 113500155203 is a prime.
It is a super-2 number, since 2×1135001553312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 113500155331.
It is not a weakly prime, because it can be changed into another prime (113500156331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56750077665 + 56750077666.
It is an arithmetic number, because the mean of its divisors is an integer number (56750077666).
Almost surely, 2113500155331 is an apocalyptic number.
113500155331 is a deficient number, since it is larger than the sum of its proper divisors (1).
113500155331 is an equidigital number, since it uses as much as digits as its factorization.
113500155331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3375, while the sum is 28.
The spelling of 113500155331 in words is "one hundred thirteen billion, five hundred million, one hundred fifty-five thousand, three hundred thirty-one".
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