1135043524541 has 4 divisors (see below), whose sum is σ = 1135293153792. Its totient is φ = 1134793895292.

The previous prime is 1135043524513. The next prime is 1135043524543. The reversal of 1135043524541 is 1454253405311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1135043524541 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1135043524495 and 1135043524504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1135043524543) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124807805 + ... + 124816898.

It is an arithmetic number, because the mean of its divisors is an integer number (283823288448).

Almost surely, 2^{1135043524541} is an apocalyptic number.

It is an amenable number.

1135043524541 is a deficient number, since it is larger than the sum of its proper divisors (249629251).

1135043524541 is an equidigital number, since it uses as much as digits as its factorization.

1135043524541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 249629250.

The product of its (nonzero) digits is 144000, while the sum is 38.

Adding to 1135043524541 its reverse (1454253405311), we get a palindrome (2589296929852).

The spelling of 1135043524541 in words is "one trillion, one hundred thirty-five billion, forty-three million, five hundred twenty-four thousand, five hundred forty-one".