113512433 has 2 divisors, whose sum is σ = 113512434. Its totient is φ = 113512432.

The previous prime is 113512397. The next prime is 113512439. The reversal of 113512433 is 334215311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97456384 + 16056049 = 9872^2 + 4007^2 .

It is a cyclic number.

It is not a de Polignac number, because 113512433 - 2⁶ = 113512369 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 113512399 and 113512408.

It is not a weakly prime, because it can be changed into another prime (113512439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56756216 + 56756217.

It is an arithmetic number, because the mean of its divisors is an integer number (56756217).

Almost surely, 2^113512433 is an apocalyptic number.

It is an amenable number.

113512433 is a deficient number, since it is larger than the sum of its proper divisors (1).

113512433 is an equidigital number, since it uses as much as digits as its factorization.

113512433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1080, while the sum is 23.

The square root of 113512433 is about 10654.2213699547. The cubic root of 113512433 is about 484.1885080085.

Adding to 113512433 its reverse (334215311), we get a palindrome (447727744).

The spelling of 113512433 in words is "one hundred thirteen million, five hundred twelve thousand, four hundred thirty-three".