Base | Representation |
---|---|
bin | 1101100010000… |
… | …10111000001001 |
3 | 21220121102100112 |
4 | 12301002320021 |
5 | 213030121022 |
6 | 15133044105 |
7 | 2545622333 |
oct | 661027011 |
9 | 256542315 |
10 | 113520137 |
11 | 590963a5 |
12 | 32026635 |
13 | 1a6986a3 |
14 | 11110453 |
15 | 9e758e2 |
hex | 6c42e09 |
113520137 has 2 divisors, whose sum is σ = 113520138. Its totient is φ = 113520136.
The previous prime is 113520119. The next prime is 113520149. The reversal of 113520137 is 731025311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113124496 + 395641 = 10636^2 + 629^2 .
It is an emirp because it is prime and its reverse (731025311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113520137 - 210 = 113519113 is a prime.
It is not a weakly prime, because it can be changed into another prime (113520437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56760068 + 56760069.
It is an arithmetic number, because the mean of its divisors is an integer number (56760069).
Almost surely, 2113520137 is an apocalyptic number.
It is an amenable number.
113520137 is a deficient number, since it is larger than the sum of its proper divisors (1).
113520137 is an equidigital number, since it uses as much as digits as its factorization.
113520137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 630, while the sum is 23.
The square root of 113520137 is about 10654.5829106540. The cubic root of 113520137 is about 484.1994615924.
Adding to 113520137 its reverse (731025311), we get a palindrome (844545448).
The spelling of 113520137 in words is "one hundred thirteen million, five hundred twenty thousand, one hundred thirty-seven".
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