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1135214454431 = 8005931417967
BaseRepresentation
bin10000100001010000000…
…011011110011010011111
311000112012001021101211202
4100201100003132122133
5122044404400020211
62225302121310115
7145005446436311
oct20412003363237
94015161241752
101135214454431
113a8494a678a2
1216401903533b
1383086577465
143cd322797b1
151e7e229353b
hex108500de69f

1135214454431 has 4 divisors (see below), whose sum is σ = 1135216672992. Its totient is φ = 1135212235872.

The previous prime is 1135214454419. The next prime is 1135214454487. The reversal of 1135214454431 is 1344544125311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1135214454431 - 210 = 1135214453407 is a prime.

It is a super-2 number, since 2×11352144544312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1135214454631) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91610 + ... + 1509576.

It is an arithmetic number, because the mean of its divisors is an integer number (283804168248).

Almost surely, 21135214454431 is an apocalyptic number.

1135214454431 is a deficient number, since it is larger than the sum of its proper divisors (2218561).

1135214454431 is an equidigital number, since it uses as much as digits as its factorization.

1135214454431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2218560.

The product of its digits is 115200, while the sum is 38.

Adding to 1135214454431 its reverse (1344544125311), we get a palindrome (2479758579742).

The spelling of 1135214454431 in words is "one trillion, one hundred thirty-five billion, two hundred fourteen million, four hundred fifty-four thousand, four hundred thirty-one".

Divisors: 1 800593 1417967 1135214454431