Base | Representation |
---|---|
bin | 11001110011111101111111… |
… | …001010011011010111100111 |
3 | 112212221122012020000000010202 |
4 | 121303331333022123113213 |
5 | 104334422400443244201 |
6 | 1041235251013141115 |
7 | 32624503151042315 |
oct | 3163757712332747 |
9 | 485848166000122 |
10 | 113522414040551 |
11 | 3319864922581a |
12 | 108954a292a79b |
13 | 4b4616b7ba3c9 |
14 | 200672abb90b5 |
15 | d1cea2701c6b |
hex | 673f7f29b5e7 |
113522414040551 has 8 divisors (see below), whose sum is σ = 114645312996864. Its totient is φ = 112399913922840.
The previous prime is 113522414040523. The next prime is 113522414040559. The reversal of 113522414040551 is 155040414225311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113522414040551 - 26 = 113522414040487 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113522414040559) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 99137555 + ... + 100276116.
It is an arithmetic number, because the mean of its divisors is an integer number (14330664124608).
Almost surely, 2113522414040551 is an apocalyptic number.
113522414040551 is a deficient number, since it is larger than the sum of its proper divisors (1122898956313).
113522414040551 is a wasteful number, since it uses less digits than its factorization.
113522414040551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 199419301.
The product of its (nonzero) digits is 96000, while the sum is 38.
Adding to 113522414040551 its reverse (155040414225311), we get a palindrome (268562828265862).
The spelling of 113522414040551 in words is "one hundred thirteen trillion, five hundred twenty-two billion, four hundred fourteen million, forty thousand, five hundred fifty-one".
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