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113534523300041 is a prime number
BaseRepresentation
bin11001110100001001010000…
…111011100101100011001001
3112212222210110010201010022222
4121310021100323211203021
5104340122200431100131
61041245012344423425
732625412220044664
oct3164112073454311
9485883403633288
10113534523300041
11331a27a2622698
1210897902177b75
134b4734b4881cc
1420071591186db
15d1d46085587b
hex674250ee58c9

113534523300041 has 2 divisors, whose sum is σ = 113534523300042. Its totient is φ = 113534523300040.

The previous prime is 113534523300019. The next prime is 113534523300049. The reversal of 113534523300041 is 140003325435311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 107033425724416 + 6501097575625 = 10345696^2 + 2549725^2 .

It is a cyclic number.

It is not a de Polignac number, because 113534523300041 - 222 = 113534519105737 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113534523299974 and 113534523300010.

It is not a weakly prime, because it can be changed into another prime (113534523300049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767261650020 + 56767261650021.

It is an arithmetic number, because the mean of its divisors is an integer number (56767261650021).

Almost surely, 2113534523300041 is an apocalyptic number.

It is an amenable number.

113534523300041 is a deficient number, since it is larger than the sum of its proper divisors (1).

113534523300041 is an equidigital number, since it uses as much as digits as its factorization.

113534523300041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 113534523300041 its reverse (140003325435311), we get a palindrome (253537848735352).

The spelling of 113534523300041 in words is "one hundred thirteen trillion, five hundred thirty-four billion, five hundred twenty-three million, three hundred thousand, forty-one".