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113535040312313 is a prime number
BaseRepresentation
bin11001110100001001101111…
…101111110101001111111001
3112212222211210011120001211122
4121310021233233311033321
5104340124230304443223
61041245135534035025
732625431065425254
oct3164115757651771
9485884704501748
10113535040312313
11331a2a38449664
1210897a27348a75
134b47401618829
1420071a7a5c09b
15d1d490e2e5c8
hex67426fbf53f9

113535040312313 has 2 divisors, whose sum is σ = 113535040312314. Its totient is φ = 113535040312312.

The previous prime is 113535040312289. The next prime is 113535040312333. The reversal of 113535040312313 is 313213040535311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 67247741022784 + 46287299289529 = 8200472^2 + 6803477^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113535040312313 is a prime.

It is not a weakly prime, because it can be changed into another prime (113535040312333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767520156156 + 56767520156157.

It is an arithmetic number, because the mean of its divisors is an integer number (56767520156157).

Almost surely, 2113535040312313 is an apocalyptic number.

It is an amenable number.

113535040312313 is a deficient number, since it is larger than the sum of its proper divisors (1).

113535040312313 is an equidigital number, since it uses as much as digits as its factorization.

113535040312313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48600, while the sum is 35.

Adding to 113535040312313 its reverse (313213040535311), we get a palindrome (426748080847624).

The spelling of 113535040312313 in words is "one hundred thirteen trillion, five hundred thirty-five billion, forty million, three hundred twelve thousand, three hundred thirteen".