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113535042345113 is a prime number
BaseRepresentation
bin11001110100001001101111…
…110111100101100010011001
3112212222211210022101100022112
4121310021233313211202121
5104340124231320020423
61041245140045402105
732625431121622634
oct3164115767454231
9485884708340275
10113535042345113
11331a2a39607964
1210897a27b69335
134b47401b7ab7c
1420071a802ac1b
15d1d4911d1a78
hex67426fde5899

113535042345113 has 2 divisors, whose sum is σ = 113535042345114. Its totient is φ = 113535042345112.

The previous prime is 113535042345103. The next prime is 113535042345143. The reversal of 113535042345113 is 311543240535311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113319367554649 + 215674790464 = 10645157^2 + 464408^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113535042345113 is a prime.

It is a super-3 number, since 3×1135350423451133 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (113535042345103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767521172556 + 56767521172557.

It is an arithmetic number, because the mean of its divisors is an integer number (56767521172557).

Almost surely, 2113535042345113 is an apocalyptic number.

It is an amenable number.

113535042345113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113535042345113 is an equidigital number, since it uses as much as digits as its factorization.

113535042345113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324000, while the sum is 41.

The spelling of 113535042345113 in words is "one hundred thirteen trillion, five hundred thirty-five billion, forty-two million, three hundred forty-five thousand, one hundred thirteen".