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113535122254051 is a prime number
BaseRepresentation
bin11001110100001001110100…
…101000011010100011100011
3112212222211222212202010202211
4121310021310220122203203
5104340124412244112201
61041245152022222551
732625433112056411
oct3164116450324343
9485884885663684
10113535122254051
11331a2a7a726703
1210897a4a884a57
134b474155a8974
1420071b48ac2b1
15d1d498218651
hex674274a1a8e3

113535122254051 has 2 divisors, whose sum is σ = 113535122254052. Its totient is φ = 113535122254050.

The previous prime is 113535122254033. The next prime is 113535122254087. The reversal of 113535122254051 is 150452221535311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113535122254051 - 27 = 113535122253923 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113535122253995 and 113535122254013.

It is not a weakly prime, because it can be changed into another prime (113535126254051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767561127025 + 56767561127026.

It is an arithmetic number, because the mean of its divisors is an integer number (56767561127026).

Almost surely, 2113535122254051 is an apocalyptic number.

113535122254051 is a deficient number, since it is larger than the sum of its proper divisors (1).

113535122254051 is an equidigital number, since it uses as much as digits as its factorization.

113535122254051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 180000, while the sum is 40.

Adding to 113535122254051 its reverse (150452221535311), we get a palindrome (263987343789362).

The spelling of 113535122254051 in words is "one hundred thirteen trillion, five hundred thirty-five billion, one hundred twenty-two million, two hundred fifty-four thousand, fifty-one".