Base | Representation |
---|---|
bin | 11001110100001010001100… |
… | …100011001111110101011011 |
3 | 112212222220000211212012220011 |
4 | 121310022030203033311123 |
5 | 104340131223012140403 |
6 | 1041245255515342351 |
7 | 32625446054050135 |
oct | 3164121443176533 |
9 | 485886024765804 |
10 | 113535523552603 |
11 | 331a31661a91a9 |
12 | 10897b411519b7 |
13 | 4b4747a783329 |
14 | 2007211cd0055 |
15 | d1d4bd586a6d |
hex | 67428c8cfd5b |
113535523552603 has 2 divisors, whose sum is σ = 113535523552604. Its totient is φ = 113535523552602.
The previous prime is 113535523552547. The next prime is 113535523552651. The reversal of 113535523552603 is 306255325535311.
It is a strong prime.
It is an emirp because it is prime and its reverse (306255325535311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113535523552603 - 221 = 113535521455451 is a prime.
It is not a weakly prime, because it can be changed into another prime (113535523552673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56767761776301 + 56767761776302.
It is an arithmetic number, because the mean of its divisors is an integer number (56767761776302).
Almost surely, 2113535523552603 is an apocalyptic number.
113535523552603 is a deficient number, since it is larger than the sum of its proper divisors (1).
113535523552603 is an equidigital number, since it uses as much as digits as its factorization.
113535523552603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6075000, while the sum is 49.
The spelling of 113535523552603 in words is "one hundred thirteen trillion, five hundred thirty-five billion, five hundred twenty-three million, five hundred fifty-two thousand, six hundred three".
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