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113541112150534 = 256770556075267
BaseRepresentation
bin11001110100001111011001…
…101010000011101000000110
3112220000102110022210102000201
4121310033121222003220012
5104340224144202304114
61041252022234401114
732626034414254435
oct3164173152035006
9486012408712021
10113541112150534
11331a5573886582
121089904089019a
134b47b5b547a03
1420075c220b11c
15d1d6e9007874
hex6743d9a83a06

113541112150534 has 4 divisors (see below), whose sum is σ = 170311668225804. Its totient is φ = 56770556075266.

The previous prime is 113541112150507. The next prime is 113541112150547. The reversal of 113541112150534 is 435051211145311.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 113541112150493 and 113541112150502.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28385278037632 + ... + 28385278037635.

It is an arithmetic number, because the mean of its divisors is an integer number (42577917056451).

Almost surely, 2113541112150534 is an apocalyptic number.

113541112150534 is a deficient number, since it is larger than the sum of its proper divisors (56770556075270).

113541112150534 is an equidigital number, since it uses as much as digits as its factorization.

113541112150534 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56770556075269.

The product of its (nonzero) digits is 36000, while the sum is 37.

Adding to 113541112150534 its reverse (435051211145311), we get a palindrome (548592323295845).

The spelling of 113541112150534 in words is "one hundred thirteen trillion, five hundred forty-one billion, one hundred twelve million, one hundred fifty thousand, five hundred thirty-four".

Divisors: 1 2 56770556075267 113541112150534