Base | Representation |
---|---|
bin | 10000100001011011110… |
… | …110000000101011000111 |
3 | 11000112200211110112012000 |
4 | 100201123312000223013 |
5 | 122100311014020320 |
6 | 2225333505000343 |
7 | 145013400616545 |
oct | 20413366005307 |
9 | 4015624415160 |
10 | 1135412251335 |
11 | 3a858668560a |
12 | 1640733230b3 |
13 | 830b853ca4b |
14 | 3cd50646d95 |
15 | 1e804814c90 |
hex | 1085bd80ac7 |
1135412251335 has 16 divisors (see below), whose sum is σ = 2018510669280. Its totient is φ = 605553200640.
The previous prime is 1135412251319. The next prime is 1135412251361. The reversal of 1135412251335 is 5331522145311.
It is a happy number.
1135412251335 is a `hidden beast` number, since 1 + 1 + 35 + 41 + 2 + 251 + 335 = 666.
It is not a de Polignac number, because 1135412251335 - 24 = 1135412251319 is a prime.
It is a super-3 number, since 3×11354122513353 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a hoax number, since the sum of its digits (36) coincides with the sum of the digits of its distinct prime factors.
It is a self number, because there is not a number n which added to its sum of digits gives 1135412251335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4205230426 + ... + 4205230695.
It is an arithmetic number, because the mean of its divisors is an integer number (126156916830).
Almost surely, 21135412251335 is an apocalyptic number.
1135412251335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1135412251335 is a deficient number, since it is larger than the sum of its proper divisors (883098417945).
1135412251335 is an equidigital number, since it uses as much as digits as its factorization.
1135412251335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8410461135 (or 8410461129 counting only the distinct ones).
The product of its digits is 54000, while the sum is 36.
Adding to 1135412251335 its reverse (5331522145311), we get a palindrome (6466934396646).
The spelling of 1135412251335 in words is "one trillion, one hundred thirty-five billion, four hundred twelve million, two hundred fifty-one thousand, three hundred thirty-five".
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