Base | Representation |
---|---|
bin | 10000100001011100011… |
… | …000001111011001011001 |
3 | 11000112201110100102002211 |
4 | 100201130120033121121 |
5 | 122100320313141122 |
6 | 2225334425155121 |
7 | 145013540111515 |
oct | 20413430173131 |
9 | 4015643312084 |
10 | 1135421224537 |
11 | 3a8590754286 |
12 | 16407632baa1 |
13 | 830ba362132 |
14 | 3cd51901145 |
15 | 1e8054d8877 |
hex | 1085c60f659 |
1135421224537 has 2 divisors, whose sum is σ = 1135421224538. Its totient is φ = 1135421224536.
The previous prime is 1135421224507. The next prime is 1135421224571. The reversal of 1135421224537 is 7354221245311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 708928636441 + 426492588096 = 841979^2 + 653064^2 .
It is a cyclic number.
It is not a de Polignac number, because 1135421224537 - 235 = 1101061486169 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1135421224537.
It is not a weakly prime, because it can be changed into another prime (1135421224507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 567710612268 + 567710612269.
It is an arithmetic number, because the mean of its divisors is an integer number (567710612269).
Almost surely, 21135421224537 is an apocalyptic number.
It is an amenable number.
1135421224537 is a deficient number, since it is larger than the sum of its proper divisors (1).
1135421224537 is an equidigital number, since it uses as much as digits as its factorization.
1135421224537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 201600, while the sum is 40.
Adding to 1135421224537 its reverse (7354221245311), we get a palindrome (8489642469848).
The spelling of 1135421224537 in words is "one trillion, one hundred thirty-five billion, four hundred twenty-one million, two hundred twenty-four thousand, five hundred thirty-seven".
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