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113543004434 = 256771502217
BaseRepresentation
bin110100110111110110…
…0001100000100010010
3101212002000012020202112
41221233230030010102
53330014002120214
6124054432345322
711126462420306
oct1515754140422
9355060166675
10113543004434
114417607a852
121a0093a5242
13a926542732
1456d1977d06
152e4819ba3e
hex1a6fb0c112

113543004434 has 4 divisors (see below), whose sum is σ = 170314506654. Its totient is φ = 56771502216.

The previous prime is 113543004401. The next prime is 113543004439. The reversal of 113543004434 is 434400345311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 77060094409 + 36482910025 = 277597^2 + 191005^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 113543004434.

It is not an unprimeable number, because it can be changed into a prime (113543004439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28385751107 + ... + 28385751110.

Almost surely, 2113543004434 is an apocalyptic number.

113543004434 is a deficient number, since it is larger than the sum of its proper divisors (56771502220).

113543004434 is an equidigital number, since it uses as much as digits as its factorization.

113543004434 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56771502219.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 113543004434 its reverse (434400345311), we get a palindrome (547943349745).

The spelling of 113543004434 in words is "one hundred thirteen billion, five hundred forty-three million, four thousand, four hundred thirty-four".

Divisors: 1 2 56771502217 113543004434