113543101345311 has 72 divisors (see below), whose sum is σ = 182707556850000. Its totient is φ = 67942892777760.

The previous prime is 113543101345307. The next prime is 113543101345339.

113543101345311 is a `hidden beast` number, since 1 + 1 + 3 + 543 + 101 + 3 + 4 + 5 + 3 + 1 + 1 = 666.

113543101345311 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 113543101345311 - 2² = 113543101345307 is a prime.

It is a super-2 number, since 2×113543101345311² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113543101345351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 74001565 + ... + 75520313.

It is an arithmetic number, because the mean of its divisors is an integer number (2537604956250).

Almost surely, 2^{113543101345311} is an apocalyptic number.

113543101345311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

113543101345311 is a deficient number, since it is larger than the sum of its proper divisors (69164455504689).

113543101345311 is an equidigital number, since it uses as much as digits as its factorization.

113543101345311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1518946 (or 1518842 counting only the distinct ones).

The product of its (nonzero) digits is 32400, while the sum is 36.

It can be divided in two parts, 11354310 and 1345311, that added together give a palindrome (12699621).

The spelling of 113543101345311 in words is "one hundred thirteen trillion, five hundred forty-three billion, one hundred one million, three hundred forty-five thousand, three hundred eleven".