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113552431132 = 2274055443969
BaseRepresentation
bin110100111000001000…
…0001001100000011100
3101212002122221011202111
41221300100021200130
53330023410244012
6124055410403404
711126635511350
oct1516020114034
9355078834674
10113552431132
1144180429208
121a010590564
13a92849336a
1456d2d0d460
152e48e0eba7
hex1a7040981c

113552431132 has 12 divisors (see below), whose sum is σ = 227104862320. Its totient is φ = 48665327616.

The previous prime is 113552431067. The next prime is 113552431133. The reversal of 113552431132 is 231134255311.

113552431132 is an admirable number.

It is a junction number, because it is equal to n+sod(n) for n = 113552431094 and 113552431103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113552431133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2027721957 + ... + 2027722012.

Almost surely, 2113552431132 is an apocalyptic number.

It is an amenable number.

113552431132 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113552431132 is a wasteful number, since it uses less digits than its factorization.

113552431132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4055443980 (or 4055443978 counting only the distinct ones).

The product of its digits is 10800, while the sum is 31.

Adding to 113552431132 its reverse (231134255311), we get a palindrome (344686686443).

The spelling of 113552431132 in words is "one hundred thirteen billion, five hundred fifty-two million, four hundred thirty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 7 14 28 4055443969 8110887938 16221775876 28388107783 56776215566 113552431132