Base | Representation |
---|---|
bin | 11001110100011010111101… |
… | …110101010001011011101011 |
3 | 112220001121111202121020021121 |
4 | 121310122331311101123223 |
5 | 104340430112214334012 |
6 | 1041301434401120111 |
7 | 32626654223224303 |
oct | 3164327565213353 |
9 | 486047452536247 |
10 | 113553530230507 |
11 | 331aa866531894 |
12 | 1089b527629037 |
13 | 4b4908a1b1323 |
14 | 200803d578603 |
15 | d1dbc430da07 |
hex | 6746bdd516eb |
113553530230507 has 2 divisors, whose sum is σ = 113553530230508. Its totient is φ = 113553530230506.
The previous prime is 113553530230499. The next prime is 113553530230513. The reversal of 113553530230507 is 705032035355311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113553530230507 - 23 = 113553530230499 is a prime.
It is not a weakly prime, because it can be changed into another prime (113553530237507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56776765115253 + 56776765115254.
It is an arithmetic number, because the mean of its divisors is an integer number (56776765115254).
Almost surely, 2113553530230507 is an apocalyptic number.
113553530230507 is a deficient number, since it is larger than the sum of its proper divisors (1).
113553530230507 is an equidigital number, since it uses as much as digits as its factorization.
113553530230507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 708750, while the sum is 43.
Adding to 113553530230507 its reverse (705032035355311), we get a palindrome (818585565585818).
The spelling of 113553530230507 in words is "one hundred thirteen trillion, five hundred fifty-three billion, five hundred thirty million, two hundred thirty thousand, five hundred seven".
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