Base | Representation |
---|---|
bin | 11001110100011011011010… |
… | …011011110101100011110010 |
3 | 112220001122202012120020012221 |
4 | 121310123122123311203302 |
5 | 104340432103041231002 |
6 | 1041301554142311254 |
7 | 32630002141115461 |
oct | 3164333233654362 |
9 | 486048665506187 |
10 | 113554010102002 |
11 | 331aaa923a03a8 |
12 | 1089b64028852a |
13 | 4b49135739662 |
14 | 20080871b09d8 |
15 | d1dc014ecc37 |
hex | 6746da6f58f2 |
113554010102002 has 4 divisors (see below), whose sum is σ = 170331015153006. Its totient is φ = 56777005051000.
The previous prime is 113554010101997. The next prime is 113554010102009. The reversal of 113554010102002 is 200201010455311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 92942691581041 + 20611318520961 = 9640679^2 + 4539969^2 .
It is not an unprimeable number, because it can be changed into a prime (113554010102009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28388502525499 + ... + 28388502525502.
Almost surely, 2113554010102002 is an apocalyptic number.
113554010102002 is a deficient number, since it is larger than the sum of its proper divisors (56777005051004).
113554010102002 is an equidigital number, since it uses as much as digits as its factorization.
113554010102002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56777005051003.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 113554010102002 its reverse (200201010455311), we get a palindrome (313755020557313).
The spelling of 113554010102002 in words is "one hundred thirteen trillion, five hundred fifty-four billion, ten million, one hundred two thousand, two".
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