Search a number
-
+
113554010102002 = 256777005051001
BaseRepresentation
bin11001110100011011011010…
…011011110101100011110010
3112220001122202012120020012221
4121310123122123311203302
5104340432103041231002
61041301554142311254
732630002141115461
oct3164333233654362
9486048665506187
10113554010102002
11331aaa923a03a8
121089b64028852a
134b49135739662
1420080871b09d8
15d1dc014ecc37
hex6746da6f58f2

113554010102002 has 4 divisors (see below), whose sum is σ = 170331015153006. Its totient is φ = 56777005051000.

The previous prime is 113554010101997. The next prime is 113554010102009. The reversal of 113554010102002 is 200201010455311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 92942691581041 + 20611318520961 = 9640679^2 + 4539969^2 .

It is not an unprimeable number, because it can be changed into a prime (113554010102009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28388502525499 + ... + 28388502525502.

Almost surely, 2113554010102002 is an apocalyptic number.

113554010102002 is a deficient number, since it is larger than the sum of its proper divisors (56777005051004).

113554010102002 is an equidigital number, since it uses as much as digits as its factorization.

113554010102002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56777005051003.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 113554010102002 its reverse (200201010455311), we get a palindrome (313755020557313).

The spelling of 113554010102002 in words is "one hundred thirteen trillion, five hundred fifty-four billion, ten million, one hundred two thousand, two".

Divisors: 1 2 56777005051001 113554010102002