Base | Representation |
---|---|
bin | 11001110100011100010110… |
… | …001011000010001100000011 |
3 | 112220001202100001102200220102 |
4 | 121310130112023002030003 |
5 | 104340441131124031433 |
6 | 1041302241423433015 |
7 | 32630036030656631 |
oct | 3164342613021403 |
9 | 486052301380812 |
10 | 113555012330243 |
11 | 332004570a6300 |
12 | 1089b87ba5576b |
13 | 4b49265276b13 |
14 | 200814033c351 |
15 | d1dc5e4be4e8 |
hex | 6747162c2303 |
113555012330243 has 24 divisors (see below), whose sum is σ = 130667724870144. Its totient is φ = 98421848213040.
The previous prime is 113555012330093. The next prime is 113555012330269. The reversal of 113555012330243 is 342033210555311.
It is not a de Polignac number, because 113555012330243 - 210 = 113555012329219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113555012330197 and 113555012330206.
It is not an unprimeable number, because it can be changed into a prime (113555012330293) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 65600171 + ... + 67308932.
It is an arithmetic number, because the mean of its divisors is an integer number (5444488536256).
Almost surely, 2113555012330243 is an apocalyptic number.
113555012330243 is a deficient number, since it is larger than the sum of its proper divisors (17112712539901).
113555012330243 is a wasteful number, since it uses less digits than its factorization.
113555012330243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 132909455 (or 132909444 counting only the distinct ones).
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 113555012330243 its reverse (342033210555311), we get a palindrome (455588222885554).
The spelling of 113555012330243 in words is "one hundred thirteen trillion, five hundred fifty-five billion, twelve million, three hundred thirty thousand, two hundred forty-three".
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