Base | Representation |
---|---|
bin | 11001110100111001010010… |
… | …001010000011110001110011 |
3 | 112220011201112110021120122111 |
4 | 121310321102022003301303 |
5 | 104341443244332304033 |
6 | 1041324420522150151 |
7 | 32632216015245256 |
oct | 3164712212036163 |
9 | 486151473246574 |
10 | 113586083478643 |
11 | 33212650a38a46 |
12 | 108a58b1652357 |
13 | 4b4c17752a529 |
14 | 200984ab3509d |
15 | d1e97c1807cd |
hex | 674e52283c73 |
113586083478643 has 2 divisors, whose sum is σ = 113586083478644. Its totient is φ = 113586083478642.
The previous prime is 113586083478577. The next prime is 113586083478649. The reversal of 113586083478643 is 346874380685311.
It is a strong prime.
It is an emirp because it is prime and its reverse (346874380685311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113586083478643 - 237 = 113448644525171 is a prime.
It is not a weakly prime, because it can be changed into another prime (113586083478649) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56793041739321 + 56793041739322.
It is an arithmetic number, because the mean of its divisors is an integer number (56793041739322).
Almost surely, 2113586083478643 is an apocalyptic number.
113586083478643 is a deficient number, since it is larger than the sum of its proper divisors (1).
113586083478643 is an equidigital number, since it uses as much as digits as its factorization.
113586083478643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 278691840, while the sum is 67.
The spelling of 113586083478643 in words is "one hundred thirteen trillion, five hundred eighty-six billion, eighty-three million, four hundred seventy-eight thousand, six hundred forty-three".
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