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11362145233 is a prime number
BaseRepresentation
bin10101001010011110…
…01001001111010001
31002022211212210002211
422211033021033101
5141232202121413
65115242112121
7551364432565
oct124517111721
932284783084
1011362145233
1149006a897a
1222511ab641
1310c0c7397a
1479b01d6a5
1546777683d
hex2a53c93d1

11362145233 has 2 divisors, whose sum is σ = 11362145234. Its totient is φ = 11362145232.

The previous prime is 11362145227. The next prime is 11362145243. The reversal of 11362145233 is 33254126311.

11362145233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10361814849 + 1000330384 = 101793^2 + 31628^2 .

It is a cyclic number.

It is not a de Polignac number, because 11362145233 - 217 = 11362014161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11362145195 and 11362145204.

It is not a weakly prime, because it can be changed into another prime (11362145243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5681072616 + 5681072617.

It is an arithmetic number, because the mean of its divisors is an integer number (5681072617).

Almost surely, 211362145233 is an apocalyptic number.

It is an amenable number.

11362145233 is a deficient number, since it is larger than the sum of its proper divisors (1).

11362145233 is an equidigital number, since it uses as much as digits as its factorization.

11362145233 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12960, while the sum is 31.

The spelling of 11362145233 in words is "eleven billion, three hundred sixty-two million, one hundred forty-five thousand, two hundred thirty-three".