Base | Representation |
---|---|
bin | 10000100010001100001… |
… | …110011111010001011001 |
3 | 11000121210101212100000112 |
4 | 100202030032133101121 |
5 | 122103441314140424 |
6 | 2225550223014105 |
7 | 145042455300422 |
oct | 20421416372131 |
9 | 4017711770015 |
10 | 1136223974489 |
11 | 3a89628a319a |
12 | 16425b13a335 |
13 | 831b77688c6 |
14 | 3cdca384649 |
15 | 1e850c0560e |
hex | 1088c39f459 |
1136223974489 has 2 divisors, whose sum is σ = 1136223974490. Its totient is φ = 1136223974488.
The previous prime is 1136223974411. The next prime is 1136223974519. The reversal of 1136223974489 is 9844793226311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 970303801600 + 165920172889 = 985040^2 + 407333^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1136223974489 is a prime.
It is a super-2 number, since 2×11362239744892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1136223974989) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 568111987244 + 568111987245.
It is an arithmetic number, because the mean of its divisors is an integer number (568111987245).
Almost surely, 21136223974489 is an apocalyptic number.
It is an amenable number.
1136223974489 is a deficient number, since it is larger than the sum of its proper divisors (1).
1136223974489 is an equidigital number, since it uses as much as digits as its factorization.
1136223974489 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15676416, while the sum is 59.
The spelling of 1136223974489 in words is "one trillion, one hundred thirty-six billion, two hundred twenty-three million, nine hundred seventy-four thousand, four hundred eighty-nine".
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