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11364097777 is a prime number
BaseRepresentation
bin10101001010101101…
…00101111011110001
31002022222112222111021
422211112211323301
5141233202112102
65115352015441
7551420144254
oct124526457361
932288488437
1011364097777
11490181194a
122251991581
1310c14a8616
1479b3ab09b
15467a10137
hex2a55a5ef1

11364097777 has 2 divisors, whose sum is σ = 11364097778. Its totient is φ = 11364097776.

The previous prime is 11364097751. The next prime is 11364097783. The reversal of 11364097777 is 77779046311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11132571121 + 231526656 = 105511^2 + 15216^2 .

It is an emirp because it is prime and its reverse (77779046311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11364097777 - 27 = 11364097649 is a prime.

It is a super-3 number, since 3×113640977773 (a number of 31 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (11364007777) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5682048888 + 5682048889.

It is an arithmetic number, because the mean of its divisors is an integer number (5682048889).

Almost surely, 211364097777 is an apocalyptic number.

It is an amenable number.

11364097777 is a deficient number, since it is larger than the sum of its proper divisors (1).

11364097777 is an equidigital number, since it uses as much as digits as its factorization.

11364097777 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1555848, while the sum is 52.

The spelling of 11364097777 in words is "eleven billion, three hundred sixty-four million, ninety-seven thousand, seven hundred seventy-seven".