Base | Representation |
---|---|
bin | 10101001100101100… |
… | …11110010001110001 |
3 | 1002101011001202111011 |
4 | 22212112132101301 |
5 | 141301443444013 |
6 | 5121150550521 |
7 | 552012401065 |
oct | 124626362161 |
9 | 32334052434 |
10 | 11380843633 |
11 | 491020a2a5 |
12 | 2257508441 |
13 | 10c4abc803 |
14 | 79d6c9aa5 |
15 | 46921bc3d |
hex | 2a659e471 |
11380843633 has 2 divisors, whose sum is σ = 11380843634. Its totient is φ = 11380843632.
The previous prime is 11380843577. The next prime is 11380843657. The reversal of 11380843633 is 33634808311.
11380843633 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11195121249 + 185722384 = 105807^2 + 13628^2 .
It is a cyclic number.
It is not a de Polignac number, because 11380843633 - 221 = 11378746481 is a prime.
It is not a weakly prime, because it can be changed into another prime (11380843333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5690421816 + 5690421817.
It is an arithmetic number, because the mean of its divisors is an integer number (5690421817).
Almost surely, 211380843633 is an apocalyptic number.
It is an amenable number.
11380843633 is a deficient number, since it is larger than the sum of its proper divisors (1).
11380843633 is an equidigital number, since it uses as much as digits as its factorization.
11380843633 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 40.
The spelling of 11380843633 in words is "eleven billion, three hundred eighty million, eight hundred forty-three thousand, six hundred thirty-three".
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