Base | Representation |
---|---|
bin | 10101001101001000… |
… | …10000011011111001 |
3 | 1002101101212100000211 |
4 | 22212210100123321 |
5 | 141303410110303 |
6 | 5121400231121 |
7 | 552055200412 |
oct | 124644203371 |
9 | 32341770024 |
10 | 11384456953 |
11 | 4912258011 |
12 | 225876b4a1 |
13 | 10c578637c |
14 | 79dd8a809 |
15 | 4696d266d |
hex | 2a69106f9 |
11384456953 has 2 divisors, whose sum is σ = 11384456954. Its totient is φ = 11384456952.
The previous prime is 11384456927. The next prime is 11384457037. The reversal of 11384456953 is 35965448311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7883131369 + 3501325584 = 88787^2 + 59172^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11384456953 is a prime.
It is a super-2 number, since 2×113844569532 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11384456897 and 11384456906.
It is not a weakly prime, because it can be changed into another prime (11384456753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5692228476 + 5692228477.
It is an arithmetic number, because the mean of its divisors is an integer number (5692228477).
Almost surely, 211384456953 is an apocalyptic number.
It is an amenable number.
11384456953 is a deficient number, since it is larger than the sum of its proper divisors (1).
11384456953 is an equidigital number, since it uses as much as digits as its factorization.
11384456953 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1555200, while the sum is 49.
The spelling of 11384456953 in words is "eleven billion, three hundred eighty-four million, four hundred fifty-six thousand, nine hundred fifty-three".
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