Search a number
-
+
11394947353 is a prime number
BaseRepresentation
bin10101001110011000…
…10001100100011001
31002102010121022011011
422213030101210121
5141314101303403
65122413133521
7552243311566
oct124714214431
932363538134
1011394947353
114918172669
12226018a2a1
1310c79ba1ca
147a151b86d
1546a5a5a6d
hex2a7311919

11394947353 has 2 divisors, whose sum is σ = 11394947354. Its totient is φ = 11394947352.

The previous prime is 11394947341. The next prime is 11394947381. The reversal of 11394947353 is 35374949311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10619714704 + 775232649 = 103052^2 + 27843^2 .

It is a cyclic number.

It is not a de Polignac number, because 11394947353 - 217 = 11394816281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11394947297 and 11394947306.

It is not a weakly prime, because it can be changed into another prime (11394947953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5697473676 + 5697473677.

It is an arithmetic number, because the mean of its divisors is an integer number (5697473677).

Almost surely, 211394947353 is an apocalyptic number.

It is an amenable number.

11394947353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11394947353 is an equidigital number, since it uses as much as digits as its factorization.

11394947353 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1224720, while the sum is 49.

The spelling of 11394947353 in words is "eleven billion, three hundred ninety-four million, nine hundred forty-seven thousand, three hundred fifty-three".