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1139947006157 = 8313734301279
BaseRepresentation
bin10000100101101010001…
…000101110100011001101
311000222101212101221100022
4100211222020232203031
5122134102413144112
62231403500311525
7145233643451231
oct20455210564315
94028355357308
101139947006157
113aa4a3403a73
12164b19b425a5
138365bb9481b
143d2609dc5c1
151e9bc9bad72
hex1096a22e8cd

1139947006157 has 4 divisors (see below), whose sum is σ = 1153681307520. Its totient is φ = 1126212704796.

The previous prime is 1139947006151. The next prime is 1139947006193. The reversal of 1139947006157 is 7516007499311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1139947006157 - 216 = 1139946940621 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1139947006099 and 1139947006108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1139947006151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6867150557 + ... + 6867150722.

It is an arithmetic number, because the mean of its divisors is an integer number (288420326880).

Almost surely, 21139947006157 is an apocalyptic number.

It is an amenable number.

1139947006157 is a deficient number, since it is larger than the sum of its proper divisors (13734301363).

1139947006157 is an equidigital number, since it uses as much as digits as its factorization.

1139947006157 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13734301362.

The product of its (nonzero) digits is 1428840, while the sum is 53.

The spelling of 1139947006157 in words is "one trillion, one hundred thirty-nine billion, nine hundred forty-seven million, six thousand, one hundred fifty-seven".

Divisors: 1 83 13734301279 1139947006157