Base | Representation |
---|---|
bin | 1101100101101… |
… | …10110100100011 |
3 | 21221111112210122 |
4 | 12302312310203 |
5 | 213140320133 |
6 | 15151150455 |
7 | 2552641031 |
oct | 662666443 |
9 | 257445718 |
10 | 113995043 |
11 | 59390188 |
12 | 3221542b |
13 | 1a8038b6 |
14 | 111d5551 |
15 | a01b498 |
hex | 6cb6d23 |
113995043 has 2 divisors, whose sum is σ = 113995044. Its totient is φ = 113995042.
The previous prime is 113995019. The next prime is 113995051. The reversal of 113995043 is 340599311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113995043 - 210 = 113994019 is a prime.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 113994994 and 113995012.
It is not a weakly prime, because it can be changed into another prime (113995093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56997521 + 56997522.
It is an arithmetic number, because the mean of its divisors is an integer number (56997522).
Almost surely, 2113995043 is an apocalyptic number.
113995043 is a deficient number, since it is larger than the sum of its proper divisors (1).
113995043 is an equidigital number, since it uses as much as digits as its factorization.
113995043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 35.
The square root of 113995043 is about 10676.8461167144. The cubic root of 113995043 is about 484.8737305467.
The spelling of 113995043 in words is "one hundred thirteen million, nine hundred ninety-five thousand, forty-three".
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