114001300123 has 2 divisors, whose sum is σ = 114001300124. Its totient is φ = 114001300122.

The previous prime is 114001300099. The next prime is 114001300157. The reversal of 114001300123 is 321003100411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114001300123 - 2⁹ = 114001299611 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114001300097 and 114001300106.

It is not a weakly prime, because it can be changed into another prime (114001300183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57000650061 + 57000650062.

It is an arithmetic number, because the mean of its divisors is an integer number (57000650062).

Almost surely, 2^114001300123 is an apocalyptic number.

114001300123 is a deficient number, since it is larger than the sum of its proper divisors (1).

114001300123 is an equidigital number, since it uses as much as digits as its factorization.

114001300123 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 114001300123 its reverse (321003100411), we get a palindrome (435004400534).

The spelling of 114001300123 in words is "one hundred fourteen billion, one million, three hundred thousand, one hundred twenty-three".