Base | Representation |
---|---|
bin | 110101000101100000… |
… | …1101110110001010001 |
3 | 101220020222012011120212 |
4 | 1222023001232301101 |
5 | 3331433404331213 |
6 | 124212134413505 |
7 | 11144031630656 |
oct | 1521301566121 |
9 | 356228164525 |
10 | 114001636433 |
11 | 44390a51863 |
12 | 1a116b01295 |
13 | a99a572409 |
14 | 5736841c2d |
15 | 2e735929a8 |
hex | 1a8b06ec51 |
114001636433 has 24 divisors (see below), whose sum is σ = 121228740864. Its totient is φ = 107091201600.
The previous prime is 114001636409. The next prime is 114001636459. The reversal of 114001636433 is 334636100411.
It is not a de Polignac number, because 114001636433 - 222 = 113997442129 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 114001636433.
It is not an unprimeable number, because it can be changed into a prime (114001636403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19561466 + ... + 19567292.
It is an arithmetic number, because the mean of its divisors is an integer number (5051197536).
Almost surely, 2114001636433 is an apocalyptic number.
It is an amenable number.
114001636433 is a deficient number, since it is larger than the sum of its proper divisors (7227104431).
114001636433 is an equidigital number, since it uses as much as digits as its factorization.
114001636433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6393 (or 6356 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 114001636433 its reverse (334636100411), we get a palindrome (448637736844).
The spelling of 114001636433 in words is "one hundred fourteen billion, one million, six hundred thirty-six thousand, four hundred thirty-three".
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