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114002113151 = 315371299733
BaseRepresentation
bin110101000101100001…
…1100011001001111111
3101220021000002101112002
41222023003203021333
53331434020110101
6124212152532515
711144035654553
oct1521303431177
9356230071462
10114002113151
1144391247a43
121a1170b113b
13a99a6ab3b4
145736927863
152e73638d6b
hex1a8b0e327f

114002113151 has 16 divisors (see below), whose sum is σ = 119929109760. Its totient is φ = 108216725760.

The previous prime is 114002113111. The next prime is 114002113177. The reversal of 114002113151 is 151311200411.

It is a cyclic number.

It is not a de Polignac number, because 114002113151 - 222 = 113997918847 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114002113111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11708081 + ... + 11717813.

It is an arithmetic number, because the mean of its divisors is an integer number (7495569360).

Almost surely, 2114002113151 is an apocalyptic number.

114002113151 is a deficient number, since it is larger than the sum of its proper divisors (5926996609).

114002113151 is an equidigital number, since it uses as much as digits as its factorization.

114002113151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16946.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 114002113151 its reverse (151311200411), we get a palindrome (265313313562).

The spelling of 114002113151 in words is "one hundred fourteen billion, two million, one hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 31 53 1643 7129 9733 220999 301723 377837 515849 11712947 15991319 69386557 2150983267 3677487521 114002113151