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11400412130011 = 47242561960213
BaseRepresentation
bin1010010111100101110110…
…0000111110101011011011
31111100212110022201102101201
42211321131200332223123
52443241021001130021
640125135501055031
72254436561136502
oct245713540765333
944325408642351
1011400412130011
1136a5984491723
121341586b57477
1364909225cbb8
142b5ad6379839
1514b83e360591
hexa5e5d83eadb

11400412130011 has 4 divisors (see below), whose sum is σ = 11642974090272. Its totient is φ = 11157850169752.

The previous prime is 11400412129901. The next prime is 11400412130059. The reversal of 11400412130011 is 11003121400411.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11400412130011 - 223 = 11400403741403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11400412134011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121280980060 + ... + 121280980153.

It is an arithmetic number, because the mean of its divisors is an integer number (2910743522568).

Almost surely, 211400412130011 is an apocalyptic number.

11400412130011 is a deficient number, since it is larger than the sum of its proper divisors (242561960261).

11400412130011 is an equidigital number, since it uses as much as digits as its factorization.

11400412130011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242561960260.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 11400412130011 its reverse (11003121400411), we get a palindrome (22403533530422).

The spelling of 11400412130011 in words is "eleven trillion, four hundred billion, four hundred twelve million, one hundred thirty thousand, eleven".

Divisors: 1 47 242561960213 11400412130011