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114005431147 is a prime number
BaseRepresentation
bin110101000101101000…
…0001101001101101011
3101220021020022221221211
41222023100031031223
53331440342244042
6124212352013551
711144106114166
oct1521320151553
9356236287854
10114005431147
1144393103893
121a1182312b7
13a99b2a06ca
14573714cadd
152e73a92017
hex1a8b40d36b

114005431147 has 2 divisors, whose sum is σ = 114005431148. Its totient is φ = 114005431146.

The previous prime is 114005431121. The next prime is 114005431157. The reversal of 114005431147 is 741134500411.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 114005431147 - 215 = 114005398379 is a prime.

It is not a weakly prime, because it can be changed into another prime (114005431157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57002715573 + 57002715574.

It is an arithmetic number, because the mean of its divisors is an integer number (57002715574).

Almost surely, 2114005431147 is an apocalyptic number.

114005431147 is a deficient number, since it is larger than the sum of its proper divisors (1).

114005431147 is an equidigital number, since it uses as much as digits as its factorization.

114005431147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 114005431147 its reverse (741134500411), we get a palindrome (855139931558).

The spelling of 114005431147 in words is "one hundred fourteen billion, five million, four hundred thirty-one thousand, one hundred forty-seven".