Base | Representation |
---|---|
bin | 10000100101110100000… |
… | …101110011110011011011 |
3 | 11000222211111122210012212 |
4 | 100211310011303303123 |
5 | 122134423141412103 |
6 | 2231432224025335 |
7 | 145241042133641 |
oct | 20456405636333 |
9 | 4028744583185 |
10 | 1140114013403 |
11 | 3aa579701a92 |
12 | 164b65a6224b |
13 | 83687669891 |
14 | 3d278c73191 |
15 | 1e9cc4a97d8 |
hex | 10974173cdb |
1140114013403 has 2 divisors, whose sum is σ = 1140114013404. Its totient is φ = 1140114013402.
The previous prime is 1140114013393. The next prime is 1140114013439. The reversal of 1140114013403 is 3043104110411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1140114013403 - 24 = 1140114013387 is a prime.
It is not a weakly prime, because it can be changed into another prime (1140114013453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570057006701 + 570057006702.
It is an arithmetic number, because the mean of its divisors is an integer number (570057006702).
Almost surely, 21140114013403 is an apocalyptic number.
1140114013403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140114013403 is an equidigital number, since it uses as much as digits as its factorization.
1140114013403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1140114013403 its reverse (3043104110411), we get a palindrome (4183218123814).
The spelling of 1140114013403 in words is "one trillion, one hundred forty billion, one hundred fourteen million, thirteen thousand, four hundred three".
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