Base | Representation |
---|---|
bin | 11001111011000110010110… |
… | …011011000000011001000111 |
3 | 112221200111000022111001022100 |
4 | 121323012112123000121013 |
5 | 104420434424204043330 |
6 | 1042252330523203143 |
7 | 33005061212363343 |
oct | 3173062633003107 |
9 | 487614008431270 |
10 | 114012430534215 |
11 | 33367444814134 |
12 | 109544583764b3 |
13 | 4b804314a4185 |
14 | 2022334130623 |
15 | d2aad1b34060 |
hex | 67b1966c0647 |
114012430534215 has 48 divisors (see below), whose sum is σ = 202131597223296. Its totient is φ = 59422836211200.
The previous prime is 114012430534213. The next prime is 114012430534241. The reversal of 114012430534215 is 512435034210411.
114012430534215 is a `hidden beast` number, since 1 + 1 + 4 + 0 + 1 + 2 + 4 + 305 + 342 + 1 + 5 = 666.
It is not a de Polignac number, because 114012430534215 - 21 = 114012430534213 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 114012430534215.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114012430534213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 39378526 + ... + 42174555.
It is an arithmetic number, because the mean of its divisors is an integer number (4211074942152).
Almost surely, 2114012430534215 is an apocalyptic number.
114012430534215 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114012430534215 is a deficient number, since it is larger than the sum of its proper divisors (88119166689081).
114012430534215 is a wasteful number, since it uses less digits than its factorization.
114012430534215 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81553800 (or 81553797 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 36.
Adding to 114012430534215 its reverse (512435034210411), we get a palindrome (626447464744626).
The spelling of 114012430534215 in words is "one hundred fourteen trillion, twelve billion, four hundred thirty million, five hundred thirty-four thousand, two hundred fifteen".
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