Base | Representation |
---|---|
bin | 11001111011000111010001… |
… | …100101011110000110110111 |
3 | 112221200120120111020022000102 |
4 | 121323013101211132012313 |
5 | 104420443442310224421 |
6 | 1042253013222104315 |
7 | 33005124624340565 |
oct | 3173072145360667 |
9 | 487616514208012 |
10 | 114013423133111 |
11 | 333679040423a7 |
12 | 1095469487b09b |
13 | 4b8055c01c6b8 |
14 | 20223c9cb2a35 |
15 | d2ab3dd5260b |
hex | 67b1d195e1b7 |
114013423133111 has 4 divisors (see below), whose sum is σ = 114019491892152. Its totient is φ = 114007354374072.
The previous prime is 114013423133041. The next prime is 114013423133173. The reversal of 114013423133111 is 111331324310411.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114013423133111 - 214 = 114013423116727 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114013423139111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3034351340 + ... + 3034388913.
It is an arithmetic number, because the mean of its divisors is an integer number (28504872973038).
Almost surely, 2114013423133111 is an apocalyptic number.
114013423133111 is a deficient number, since it is larger than the sum of its proper divisors (6068759041).
114013423133111 is an equidigital number, since it uses as much as digits as its factorization.
114013423133111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6068759040.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 114013423133111 its reverse (111331324310411), we get a palindrome (225344747443522).
The spelling of 114013423133111 in words is "one hundred fourteen trillion, thirteen billion, four hundred twenty-three million, one hundred thirty-three thousand, one hundred eleven".
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