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114014540332249 is a prime number
BaseRepresentation
bin11001111011001000010100…
…001011001111110011011001
3112221200200110100102220010021
4121323020110023033303121
5104421003234311112444
61042253320131350441
733005164411356124
oct3173102413176331
9487620410386107
10114014540332249
1133368327734677
1210954946a52421
134b806a961298b
14202249440b3bb
15d2aba6e84584
hex67b2142cfcd9

114014540332249 has 2 divisors, whose sum is σ = 114014540332250. Its totient is φ = 114014540332248.

The previous prime is 114014540332213. The next prime is 114014540332313. The reversal of 114014540332249 is 942233045410411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 109723676658649 + 4290863673600 = 10474907^2 + 2071440^2 .

It is an emirp because it is prime and its reverse (942233045410411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114014540332249 - 233 = 114005950397657 is a prime.

It is a super-2 number, since 2×1140145403322492 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114014540302249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57007270166124 + 57007270166125.

It is an arithmetic number, because the mean of its divisors is an integer number (57007270166125).

Almost surely, 2114014540332249 is an apocalyptic number.

It is an amenable number.

114014540332249 is a deficient number, since it is larger than the sum of its proper divisors (1).

114014540332249 is an equidigital number, since it uses as much as digits as its factorization.

114014540332249 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 43.

The spelling of 114014540332249 in words is "one hundred fourteen trillion, fourteen billion, five hundred forty million, three hundred thirty-two thousand, two hundred forty-nine".