Base | Representation |
---|---|
bin | 110101000101111010… |
… | …1001010101101010011 |
3 | 101220021220120012212001 |
4 | 1222023311022231103 |
5 | 3332000332321321 |
6 | 124213335414431 |
7 | 11144254350166 |
oct | 1521365125523 |
9 | 356256505761 |
10 | 114015120211 |
11 | 44398621383 |
12 | 1a11b524417 |
13 | a9a02b3895 |
14 | 5738551add |
15 | 2e74857c91 |
hex | 1a8bd4ab53 |
114015120211 has 2 divisors, whose sum is σ = 114015120212. Its totient is φ = 114015120210.
The previous prime is 114015120203. The next prime is 114015120251. The reversal of 114015120211 is 112021510411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114015120211 - 23 = 114015120203 is a prime.
It is not a weakly prime, because it can be changed into another prime (114015120251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57007560105 + 57007560106.
It is an arithmetic number, because the mean of its divisors is an integer number (57007560106).
Almost surely, 2114015120211 is an apocalyptic number.
114015120211 is a deficient number, since it is larger than the sum of its proper divisors (1).
114015120211 is an equidigital number, since it uses as much as digits as its factorization.
114015120211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 114015120211 its reverse (112021510411), we get a palindrome (226036630622).
The spelling of 114015120211 in words is "one hundred fourteen billion, fifteen million, one hundred twenty thousand, two hundred eleven".
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