Base | Representation |
---|---|
bin | 110101000110000100… |
… | …0111011010011100011 |
3 | 101220022021022101012012 |
4 | 1222030020323103203 |
5 | 3332003144100003 |
6 | 124214042423135 |
7 | 11144346362501 |
oct | 1521410732343 |
9 | 356267271165 |
10 | 114020300003 |
11 | 443a0539aa5 |
12 | 1a121201aab |
13 | a9a13a844c |
14 | 57390dd671 |
15 | 2e7502c8d8 |
hex | 1a8c23b4e3 |
114020300003 has 2 divisors, whose sum is σ = 114020300004. Its totient is φ = 114020300002.
The previous prime is 114020299997. The next prime is 114020300011. The reversal of 114020300003 is 300003020411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114020300003 - 28 = 114020299747 is a prime.
It is not a weakly prime, because it can be changed into another prime (114020300083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57010150001 + 57010150002.
It is an arithmetic number, because the mean of its divisors is an integer number (57010150002).
Almost surely, 2114020300003 is an apocalyptic number.
114020300003 is a deficient number, since it is larger than the sum of its proper divisors (1).
114020300003 is an equidigital number, since it uses as much as digits as its factorization.
114020300003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 14.
Adding to 114020300003 its reverse (300003020411), we get a palindrome (414023320414).
The spelling of 114020300003 in words is "one hundred fourteen billion, twenty million, three hundred thousand, three".
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