Search a number
-
+
1140211333303 = 7223269619047
BaseRepresentation
bin10000100101111001111…
…001000011100010110111
311001000002021210011000121
4100211321321003202313
5122140123100131203
62231450021552411
7145243333264300
oct20457171034267
94030067704017
101140211333303
113aa619632959
12164b92575707
13836a1882513
143d287b677a7
151e9d5cd00bd
hex10979e438b7

1140211333303 has 6 divisors (see below), whose sum is σ = 1326368285736. Its totient is φ = 977323999932.

The previous prime is 1140211333291. The next prime is 1140211333369. The reversal of 1140211333303 is 3033331120411.

It is not a de Polignac number, because 1140211333303 - 25 = 1140211333271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140211363303) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 11634809475 + ... + 11634809572.

It is an arithmetic number, because the mean of its divisors is an integer number (221061380956).

Almost surely, 21140211333303 is an apocalyptic number.

1140211333303 is a deficient number, since it is larger than the sum of its proper divisors (186156952433).

1140211333303 is an equidigital number, since it uses as much as digits as its factorization.

1140211333303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23269619061 (or 23269619054 counting only the distinct ones).

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1140211333303 its reverse (3033331120411), we get a palindrome (4173542453714).

The spelling of 1140211333303 in words is "one trillion, one hundred forty billion, two hundred eleven million, three hundred thirty-three thousand, three hundred three".

Divisors: 1 7 49 23269619047 162887333329 1140211333303