1140220133 has 4 divisors (see below), whose sum is σ = 1227929388. Its totient is φ = 1052510880.

The previous prime is 1140220117. The next prime is 1140220171. The reversal of 1140220133 is 3310220411.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3310220411 = 3931 ⋅842081.

It can be written as a sum of positive squares in 2 ways, for example, as 346220449 + 793999684 = 18607^2 + 28178^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140220133 - 2⁴ = 1140220117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1140220183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43854608 + ... + 43854633.

It is an arithmetic number, because the mean of its divisors is an integer number (306982347).

Almost surely, 2^1140220133 is an apocalyptic number.

1140220133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1140220133 is a deficient number, since it is larger than the sum of its proper divisors (87709255).

1140220133 is an equidigital number, since it uses as much as digits as its factorization.

1140220133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87709254.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1140220133 is about 33767.1457633008. The cubic root of 1140220133 is about 1044.7111624368.

Adding to 1140220133 its reverse (3310220411), we get a palindrome (4450440544).

The spelling of 1140220133 in words is "one billion, one hundred forty million, two hundred twenty thousand, one hundred thirty-three".