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1140220134 = 232193333977
BaseRepresentation
bin100001111110110…
…0110000011100110
32221110112011222100
41003331212003212
54313344021014
6305050512530
740153465644
oct10375460346
92843464870
101140220134
11535696299
12279a35746
131522c3791
14ab60c194
156a17d009
hex43f660e6

1140220134 has 24 divisors (see below), whose sum is σ = 2600502840. Its totient is φ = 360069408.

The previous prime is 1140220117. The next prime is 1140220171. The reversal of 1140220134 is 4310220411.

1140220134 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a Curzon number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1666647 + ... + 1667330.

It is an arithmetic number, because the mean of its divisors is an integer number (108354285).

Almost surely, 21140220134 is an apocalyptic number.

1140220134 is an abundant number, since it is smaller than the sum of its proper divisors (1460282706).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1140220134 is a wasteful number, since it uses less digits than its factorization.

1140220134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3334004 (or 3334001 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

The square root of 1140220134 is about 33767.1457781080. The cubic root of 1140220134 is about 1044.7111627422.

Adding to 1140220134 its reverse (4310220411), we get a palindrome (5450440545).

The spelling of 1140220134 in words is "one billion, one hundred forty million, two hundred twenty thousand, one hundred thirty-four".

Divisors: 1 2 3 6 9 18 19 38 57 114 171 342 3333977 6667954 10001931 20003862 30005793 60011586 63345563 126691126 190036689 380073378 570110067 1140220134