Base | Representation |
---|---|
bin | 10101001111010000… |
… | …11100011111110011 |
3 | 1002102122111111012001 |
4 | 22213220130133303 |
5 | 141322444112042 |
6 | 5123235314431 |
7 | 552363136603 |
oct | 124750343763 |
9 | 32378444161 |
10 | 11402332147 |
11 | 49213569a8 |
12 | 226274ba17 |
13 | 10c93a45cb |
14 | 7a24c0c03 |
15 | 46b063bb7 |
hex | 2a7a1c7f3 |
11402332147 has 2 divisors, whose sum is σ = 11402332148. Its totient is φ = 11402332146.
The previous prime is 11402332141. The next prime is 11402332159. The reversal of 11402332147 is 74123320411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11402332147 - 211 = 11402330099 is a prime.
It is not a weakly prime, because it can be changed into another prime (11402332141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701166073 + 5701166074.
It is an arithmetic number, because the mean of its divisors is an integer number (5701166074).
Almost surely, 211402332147 is an apocalyptic number.
11402332147 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402332147 is an equidigital number, since it uses as much as digits as its factorization.
11402332147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 28.
Adding to 11402332147 its reverse (74123320411), we get a palindrome (85525652558).
The spelling of 11402332147 in words is "eleven billion, four hundred two million, three hundred thirty-two thousand, one hundred forty-seven".
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