Base | Representation |
---|---|
bin | 10101001111010001… |
… | …10000100100100011 |
3 | 1002102122122122222101 |
4 | 22213220300210203 |
5 | 141323004224441 |
6 | 5123241151231 |
7 | 552363631405 |
oct | 124750604443 |
9 | 32378578871 |
10 | 11402414371 |
11 | 4921402757 |
12 | 226278b517 |
13 | 10c9402b6a |
14 | 7a2502b75 |
15 | 46b07d231 |
hex | 2a7a30923 |
11402414371 has 2 divisors, whose sum is σ = 11402414372. Its totient is φ = 11402414370.
The previous prime is 11402414341. The next prime is 11402414377. The reversal of 11402414371 is 17341420411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11402414371 - 25 = 11402414339 is a prime.
It is not a weakly prime, because it can be changed into another prime (11402414377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701207185 + 5701207186.
It is an arithmetic number, because the mean of its divisors is an integer number (5701207186).
Almost surely, 211402414371 is an apocalyptic number.
11402414371 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402414371 is an equidigital number, since it uses as much as digits as its factorization.
11402414371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 11402414371 its reverse (17341420411), we get a palindrome (28743834782).
The spelling of 11402414371 in words is "eleven billion, four hundred two million, four hundred fourteen thousand, three hundred seventy-one".
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