Base | Representation |
---|---|
bin | 10101001111010001… |
… | …10000101010001011 |
3 | 1002102122122200110201 |
4 | 22213220300222023 |
5 | 141323004232411 |
6 | 5123241153031 |
7 | 552363632431 |
oct | 124750605213 |
9 | 32378580421 |
10 | 11402414731 |
11 | 4921402a54 |
12 | 226278b777 |
13 | 10c9403086 |
14 | 7a2502d51 |
15 | 46b07d3c1 |
hex | 2a7a30a8b |
11402414731 has 2 divisors, whose sum is σ = 11402414732. Its totient is φ = 11402414730.
The previous prime is 11402414713. The next prime is 11402414741. The reversal of 11402414731 is 13741420411.
Together with previous prime (11402414713) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11402414731 - 213 = 11402406539 is a prime.
It is a super-2 number, since 2×114024147312 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11402414731.
It is not a weakly prime, because it can be changed into another prime (11402414741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701207365 + 5701207366.
It is an arithmetic number, because the mean of its divisors is an integer number (5701207366).
Almost surely, 211402414731 is an apocalyptic number.
11402414731 is a deficient number, since it is larger than the sum of its proper divisors (1).
11402414731 is an equidigital number, since it uses as much as digits as its factorization.
11402414731 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
The spelling of 11402414731 in words is "eleven billion, four hundred two million, four hundred fourteen thousand, seven hundred thirty-one".
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