Base | Representation |
---|---|
bin | 1010010111101101011001… |
… | …1000101110111000110001 |
3 | 1111101001200122112110120121 |
4 | 2211323112120232320301 |
5 | 2443304144120330223 |
6 | 40130113021410241 |
7 | 2254541043634051 |
oct | 245732630567061 |
9 | 44331618473517 |
10 | 11402440011313 |
11 | 36a682514198a |
12 | 1341a52109981 |
13 | 649326419a70 |
14 | 2b5c49811561 |
15 | 14b90c3ce15d |
hex | a5ed662ee31 |
11402440011313 has 32 divisors (see below), whose sum is σ = 12920543596800. Its totient is φ = 9988399008000.
The previous prime is 11402440011299. The next prime is 11402440011377. The reversal of 11402440011313 is 31311004420411.
It is a de Polignac number, because none of the positive numbers 2k-11402440011313 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11402440011383) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 136775023 + ... + 136858363.
It is an arithmetic number, because the mean of its divisors is an integer number (403766987400).
Almost surely, 211402440011313 is an apocalyptic number.
11402440011313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11402440011313 is a deficient number, since it is larger than the sum of its proper divisors (1518103585487).
11402440011313 is a wasteful number, since it uses less digits than its factorization.
11402440011313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 89593.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 11402440011313 its reverse (31311004420411), we get a palindrome (42713444431724).
The spelling of 11402440011313 in words is "eleven trillion, four hundred two billion, four hundred forty million, eleven thousand, three hundred thirteen".
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