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1140253225537 is a prime number
BaseRepresentation
bin10000100101111100011…
…000110111001001000001
311001000012012121111100211
4100211330120313021001
5122140214311204122
62231454115514121
7145244352333136
oct20457430671101
94030165544324
101140253225537
113aa640246138
12164ba45b8941
13836aa45c41a
143d28d55058d
151e9d9807877
hex1097c637241

1140253225537 has 2 divisors, whose sum is σ = 1140253225538. Its totient is φ = 1140253225536.

The previous prime is 1140253225493. The next prime is 1140253225549. The reversal of 1140253225537 is 7355223520411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1139067387441 + 1185838096 = 1067271^2 + 34436^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140253225537 - 215 = 1140253192769 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1140253225537.

It is not a weakly prime, because it can be changed into another prime (1140253225337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570126612768 + 570126612769.

It is an arithmetic number, because the mean of its divisors is an integer number (570126612769).

Almost surely, 21140253225537 is an apocalyptic number.

It is an amenable number.

1140253225537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140253225537 is an equidigital number, since it uses as much as digits as its factorization.

1140253225537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252000, while the sum is 40.

Adding to 1140253225537 its reverse (7355223520411), we get a palindrome (8495476745948).

The spelling of 1140253225537 in words is "one trillion, one hundred forty billion, two hundred fifty-three million, two hundred twenty-five thousand, five hundred thirty-seven".