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114030021521247 = 3137227740453349
BaseRepresentation
bin11001111011010110101110…
…111011010010111101011111
3112221202011102021000210000120
4121323112232323102331133
5104421231441002134442
61042304400235130023
733006253143324666
oct3173265673227537
9487664367023016
10114030021521247
1133373951435047
12109579475a3913
134b81ca5a58940
1420231224cbddd
15d2b2b11484ec
hex67b5aeed2f5f

114030021521247 has 16 divisors (see below), whose sum is σ = 163737684952800. Its totient is φ = 70171348321152.

The previous prime is 114030021521191. The next prime is 114030021521261. The reversal of 114030021521247 is 742125120030411.

It is not a de Polignac number, because 114030021521247 - 212 = 114030021517151 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114030021521287) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17407872 + ... + 23045477.

It is an arithmetic number, because the mean of its divisors is an integer number (10233605309550).

Almost surely, 2114030021521247 is an apocalyptic number.

114030021521247 is a deficient number, since it is larger than the sum of its proper divisors (49707663431553).

114030021521247 is a wasteful number, since it uses less digits than its factorization.

114030021521247 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40525642.

The product of its (nonzero) digits is 13440, while the sum is 33.

Adding to 114030021521247 its reverse (742125120030411), we get a palindrome (856155141551658).

The spelling of 114030021521247 in words is "one hundred fourteen trillion, thirty billion, twenty-one million, five hundred twenty-one thousand, two hundred forty-seven".

Divisors: 1 3 13 39 72277 216831 939601 2818803 40453349 121360047 525893537 1577680611 2923846705673 8771540117019 38010007173749 114030021521247