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114030021521246 = 257015010760623
BaseRepresentation
bin11001111011010110101110…
…111011010010111101011110
3112221202011102021000210000112
4121323112232323102331132
5104421231441002134441
61042304400235130022
733006253143324665
oct3173265673227536
9487664367023015
10114030021521246
1133373951435046
12109579475a3912
134b81ca5a5893c
1420231224cbddc
15d2b2b11484eb
hex67b5aeed2f5e

114030021521246 has 4 divisors (see below), whose sum is σ = 171045032281872. Its totient is φ = 57015010760622.

The previous prime is 114030021521191. The next prime is 114030021521261. The reversal of 114030021521246 is 642125120030411.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28507505380310 + ... + 28507505380313.

It is an arithmetic number, because the mean of its divisors is an integer number (42761258070468).

Almost surely, 2114030021521246 is an apocalyptic number.

114030021521246 is a deficient number, since it is larger than the sum of its proper divisors (57015010760626).

114030021521246 is an equidigital number, since it uses as much as digits as its factorization.

114030021521246 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57015010760625.

The product of its (nonzero) digits is 11520, while the sum is 32.

Adding to 114030021521246 its reverse (642125120030411), we get a palindrome (756155141551657).

The spelling of 114030021521246 in words is "one hundred fourteen trillion, thirty billion, twenty-one million, five hundred twenty-one thousand, two hundred forty-six".

Divisors: 1 2 57015010760623 114030021521246